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Proofgold Proof

pf
Let x0 of type ι be given.
Assume H0: ordinal x0.
Let x1 of type ιο be given.
Apply andI with PSNo x0 x1SNoElts_ x0, ∀ x2 . x2x0exactly1of2 ((λ x3 . SetAdjoin x3 (Sing 1)) x2PSNo x0 x1) (x2PSNo x0 x1) leaving 2 subgoals.
Let x2 of type ι be given.
Assume H1: x2PSNo x0 x1.
Apply binunionE with {x3 ∈ x0|x1 x3}, {(λ x4 . SetAdjoin x4 (Sing 1)) x3|x3 ∈ x0,not (x1 x3)}, x2, x2SNoElts_ x0 leaving 3 subgoals.
The subproof is completed by applying H1.
Assume H2: x2{x3 ∈ x0|x1 x3}.
Apply SepE with x0, x1, x2, x2SNoElts_ x0 leaving 2 subgoals.
The subproof is completed by applying H2.
Assume H3: x2x0.
Assume H4: x1 x2.
Apply binunionI1 with x0, {(λ x4 . SetAdjoin x4 (Sing 1)) x3|x3 ∈ x0}, x2.
The subproof is completed by applying H3.
Assume H2: x2{(λ x4 . SetAdjoin x4 (Sing 1)) x3|x3 ∈ x0,not (x1 x3)}.
Apply ReplSepE_impred with x0, λ x3 . not (x1 x3), λ x3 . (λ x4 . SetAdjoin x4 (Sing 1)) x3, x2, x2SNoElts_ x0 leaving 2 subgoals.
The subproof is completed by applying H2.
Let x3 of type ι be given.
Assume H3: x3x0.
Assume H4: not (x1 x3).
Assume H5: x2 = (λ x4 . SetAdjoin x4 (Sing 1)) x3.
Apply binunionI2 with x0, {(λ x5 . SetAdjoin x5 (Sing 1)) x4|x4 ∈ x0}, x2.
Apply H5 with λ x4 x5 . x5{(λ x7 . SetAdjoin x7 (Sing 1)) x6|x6 ∈ x0}.
Apply ReplI with x0, λ x4 . (λ x5 . SetAdjoin x5 (Sing 1)) x4, x3.
The subproof is completed by applying H3.
Let x2 of type ι be given.
Assume H1: x2x0.
Claim L2: ...
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Apply xm with x1 x2, exactly1of2 ((λ x3 . SetAdjoin x3 (Sing 1)) x2PSNo x0 x1) (x2PSNo x0 x1) leaving 2 subgoals.
Assume H3: x1 x2.
Apply exactly1of2_I2 with (λ x3 . SetAdjoin x3 (Sing 1)) x2PSNo x0 x1, x2PSNo x0 x1 leaving 2 subgoals.
Assume H4: (λ x3 . SetAdjoin x3 (Sing 1)) x2PSNo x0 x1.
Apply binunionE with {x3 ∈ x0|x1 x3}, {(λ x4 . SetAdjoin x4 (Sing 1)) x3|x3 ∈ x0,not (x1 x3)}, (λ x3 . SetAdjoin x3 (Sing 1)) x2, False leaving 3 subgoals.
The subproof is completed by applying H4.
Assume H5: (λ x3 . SetAdjoin x3 (Sing 1)) x2{x3 ∈ x0|x1 x3}.
Apply SepE with x0, x1, (λ x3 . SetAdjoin x3 (Sing 1)) x2, False leaving 2 subgoals.
The subproof is completed by applying H5.
Assume H6: (λ x3 . SetAdjoin x3 (Sing 1)) x2x0.
Assume H7: x1 ((λ x3 . SetAdjoin x3 (Sing 1)) x2).
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