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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Assume H0: ba9d8.. x0.
Assume H1: aa8d2.. (4ae4a.. x0) x1 x2.
Apply unknownprop_8e9afa6cbe34c70175f6c4dbdd044465af8aeced2be56c04dd43afb3a9abc68a with x1, 4ae4a.. x0, x2, ∃ x3 . and (x2 = prim3 x3) (aa8d2.. x0 x1 x3) leaving 4 subgoals.
Apply unknownprop_11171438c9340577bc5ca6838eccea0ebdb4279227053bf618ee42741f7851b4 with x0.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
Assume H2: and (4ae4a.. x0 = 4a7ef..) (x2 = x1).
Apply H2 with ∃ x3 . and (x2 = prim3 x3) (aa8d2.. x0 x1 x3).
Assume H3: 4ae4a.. x0 = 4a7ef...
Apply FalseE with x2 = x1∃ x3 . and (x2 = prim3 x3) (aa8d2.. x0 x1 x3).
Apply unknownprop_2602cf2bdb1e417af7ff1134e4c9ee68b103b598c85667d3a4d01fe3c406ee63 with x0.
The subproof is completed by applying H3.
Assume H2: ∃ x3 x4 . and (and (4ae4a.. x0 = 4ae4a.. x3) (x2 = prim3 x4)) (aa8d2.. x3 x1 x4).
Apply H2 with ∃ x3 . and (x2 = prim3 x3) (aa8d2.. x0 x1 x3).
Let x3 of type ι be given.
Assume H3: (λ x4 . ∃ x5 . and (and (4ae4a.. x0 = 4ae4a.. x4) (x2 = prim3 x5)) (aa8d2.. x4 x1 x5)) x3.
Apply H3 with ∃ x4 . and (x2 = prim3 x4) (aa8d2.. x0 x1 x4).
Let x4 of type ι be given.
Assume H4: (λ x5 . and (and (4ae4a.. x0 = 4ae4a.. x3) (x2 = prim3 x5)) (aa8d2.. x3 x1 x5)) x4.
Apply H4 with ∃ x5 . and (x2 = prim3 x5) (aa8d2.. x0 x1 x5).
Assume H5: and (4ae4a.. x0 = 4ae4a.. x3) (x2 = prim3 x4).
Apply H5 with aa8d2.. x3 x1 x4∃ x5 . and (x2 = prim3 x5) (aa8d2.. x0 x1 x5).
Assume H6: 4ae4a.. x0 = 4ae4a.. x3.
Assume H7: x2 = prim3 x4.
Apply unknownprop_684cb1205e38822a7a824f8a0440cb0f546e66d657860b857331eee8a38df013 with x0, x3, λ x5 x6 . aa8d2.. x5 x1 x4∃ x7 . and (x2 = prim3 x7) (aa8d2.. x0 x1 x7) leaving 2 subgoals.
The subproof is completed by applying H6.
Assume H8: aa8d2.. x0 x1 x4.
Let x5 of type ο be given.
Assume H9: ∀ x6 . and (x2 = prim3 x6) (aa8d2.. x0 x1 x6)x5.
Apply H9 with x4.
Apply andI with x2 = prim3 x4, aa8d2.. x0 x1 x4 leaving 2 subgoals.
The subproof is completed by applying H7.
The subproof is completed by applying H8.