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Proofgold Proof

pf
Let x0 of type ι be given.
Apply add_nat_SR with x0, 0, λ x1 x2 . x2 = ordsucc x0 leaving 2 subgoals.
The subproof is completed by applying nat_0.
Apply add_nat_0R with x0, λ x1 x2 . ordsucc x2 = ordsucc x0.
Let x1 of type ιιο be given.
Assume H0: x1 (ordsucc x0) (ordsucc x0).
The subproof is completed by applying H0.