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Proofgold Proof

pf
Let x0 of type ι be given.
Assume H0: ordinal x0.
Claim L1: SNo x0
Apply ordinal_SNo with x0.
The subproof is completed by applying H0.
Claim L2: SNoLev x0 = x0
Apply ordinal_SNoLev with x0.
The subproof is completed by applying H0.
Apply Empty_Subq_eq with SNoR x0.
Let x1 of type ι be given.
Assume H3: x1SNoR x0.
Apply SNoR_E with x0, x1, x10 leaving 3 subgoals.
The subproof is completed by applying L1.
The subproof is completed by applying H3.
Assume H4: SNo x1.
Apply L2 with λ x2 x3 . SNoLev x1x3SNoLt x0 x1x10.
Assume H5: SNoLev x1x0.
Assume H6: SNoLt x0 x1.
Apply FalseE with x10.
Apply SNoLt_irref with x1.
Apply SNoLt_tra with x1, x0, x1 leaving 5 subgoals.
The subproof is completed by applying H4.
The subproof is completed by applying L1.
The subproof is completed by applying H4.
Apply ordinal_SNoLev_max with x0, x1 leaving 3 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.