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Proofgold Proof

pf
Let x0 of type ι be given.
Assume H0: struct_r_r_e_e x0.
Apply H0 with λ x1 . x1 = pack_r_r_e_e (ap x1 0) (decode_r (ap x1 1)) (decode_r (ap x1 2)) (ap x1 3) (ap x1 4).
Let x1 of type ι be given.
Let x2 of type ιιο be given.
Let x3 of type ιιο be given.
Let x4 of type ι be given.
Assume H1: x4x1.
Let x5 of type ι be given.
Assume H2: x5x1.
Apply pack_r_r_e_e_0_eq2 with x1, x2, x3, x4, x5, λ x6 x7 . pack_r_r_e_e x1 x2 x3 x4 x5 = pack_r_r_e_e x6 (decode_r (ap (pack_r_r_e_e x1 x2 x3 x4 x5) 1)) (decode_r (ap (pack_r_r_e_e x1 x2 x3 x4 x5) 2)) (ap (pack_r_r_e_e x1 x2 x3 x4 x5) 3) (ap (pack_r_r_e_e x1 x2 x3 x4 x5) 4).
Apply pack_r_r_e_e_3_eq2 with x1, x2, x3, x4, x5, λ x6 x7 . pack_r_r_e_e x1 x2 x3 x4 x5 = pack_r_r_e_e x1 (decode_r (ap (pack_r_r_e_e x1 x2 x3 x4 x5) 1)) (decode_r (ap (pack_r_r_e_e x1 x2 x3 x4 x5) 2)) x6 (ap (pack_r_r_e_e x1 x2 x3 x4 x5) 4).
Apply pack_r_r_e_e_4_eq2 with x1, x2, x3, x4, x5, λ x6 x7 . pack_r_r_e_e x1 x2 x3 x4 x5 = pack_r_r_e_e x1 (decode_r (ap (pack_r_r_e_e x1 x2 x3 x4 x5) 1)) (decode_r (ap (pack_r_r_e_e x1 x2 x3 x4 x5) 2)) x4 x6.
Apply pack_r_r_e_e_ext with x1, x2, decode_r (ap (pack_r_r_e_e x1 x2 x3 x4 x5) 1), x3, decode_r (ap (pack_r_r_e_e x1 x2 x3 x4 x5) 2), x4, x5 leaving 2 subgoals.
Let x6 of type ι be given.
Assume H3: x6x1.
Let x7 of type ι be given.
Assume H4: x7x1.
Apply pack_r_r_e_e_1_eq2 with x1, x2, x3, x4, x5, x6, x7, λ x8 x9 : ο . iff (x2 x6 x7) x8 leaving 3 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying iff_refl with x2 x6 x7.
Let x6 of type ι be given.
Assume H3: x6x1.
Let x7 of type ι be given.
Assume H4: x7x1.
Apply pack_r_r_e_e_2_eq2 with x1, x2, x3, x4, x5, x6, x7, λ x8 x9 : ο . iff (x3 x6 x7) x8 leaving 3 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying iff_refl with x3 x6 x7.