Let x0 of type ι be given.
Apply xm with
SNoL x0 = 0,
or (SNoL x0 = 0) (∃ x1 . SNo_max_of (SNoL x0) x1) leaving 2 subgoals.
The subproof is completed by applying orIL with
SNoL x0 = 0,
∃ x1 . SNo_max_of (SNoL x0) x1.
Assume H1:
SNoL x0 = 0 ⟶ ∀ x1 : ο . x1.
Apply orIR with
SNoL x0 = 0,
∃ x1 . SNo_max_of (SNoL x0) x1.
Apply finite_max_exists with
SNoL x0 leaving 3 subgoals.
Let x1 of type ι be given.
Assume H2:
x1 ∈ SNoL x0.
Apply SNoS_E2 with
omega,
x0,
SNo x1 leaving 3 subgoals.
The subproof is completed by applying omega_ordinal.
The subproof is completed by applying H0.
Apply SNoL_E with
x0,
x1,
SNo x1 leaving 3 subgoals.
The subproof is completed by applying H5.
The subproof is completed by applying H2.
The subproof is completed by applying H7.
Apply SNoS_omega_SNoL_finite with
x0.
The subproof is completed by applying H0.
The subproof is completed by applying H1.