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Proofgold Proof

pf
Let x0 of type ιι be given.
Let x1 of type ιο be given.
Let x2 of type ιι be given.
Assume H0: ∀ x3 . x1 x3x1 (x0 x3).
Assume H1: ∀ x3 . x1 x3x2 (x0 x3) = x0 (x2 x3).
Let x3 of type ι be given.
Assume H2: x1 x3.
Apply unknownprop_1ecba3dd5eafa4f5c4681522469f6140788e091a78ad9f01e97cc0b6f2c0488f with x0, x1, x2, ChurchNum_ii_6 ChurchNum2 x0 x3, λ x4 x5 . x5 = ChurchNum_ii_6 ChurchNum2 x0 (ChurchNum_ii_6 ChurchNum2 x0 (x2 x3)) leaving 4 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
Apply unknownprop_15156acfaef83289041d2fede437e15a29e8b8de66c5ea43e1171f433b1a0acd with x0, x1, x3 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H2.
Apply unknownprop_1ecba3dd5eafa4f5c4681522469f6140788e091a78ad9f01e97cc0b6f2c0488f with x0, x1, x2, x3, λ x4 x5 . ChurchNum_ii_6 ChurchNum2 x0 x5 = ChurchNum_ii_6 ChurchNum2 x0 (ChurchNum_ii_6 ChurchNum2 x0 (x2 x3)) leaving 4 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
Let x4 of type ιιο be given.
The subproof is completed by applying H3.