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Proofgold Proof

pf
Let x0 of type ο be given.
Let x1 of type ο be given.
Assume H0: exactly1of2 x0 x1.
Apply exactly1of2_E with x0, x1, x0 ⟶ not x1 leaving 3 subgoals.
The subproof is completed by applying H0.
Assume H1: x0.
Assume H2: not x1.
Assume H3: x0.
The subproof is completed by applying H2.
Assume H1: not x0.
Assume H2: x1.
Assume H3: x0.
Apply H1 with not x1.
The subproof is completed by applying H3.
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