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Proofgold Term Root Disambiguation

∀ x0 x1 . x1{x2 ∈ setexp x0 x0|bij x0 x0 (ap x2)}explicit_Group_inverse {x3 ∈ setexp x0 x0|bij x0 x0 (ap x3)} (λ x3 x4 . lam x0 (λ x5 . ap x4 (ap x3 x5))) x1 = lam x0 (inv x0 (ap x1))
as obj
-
as prop
9b221..explicit_Group_symgroup_inv_eq
theory
HotG
stx
a0c68..
address
TMSEX..explicit_Group_symgroup_inv_eq